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gafmax
- % [BestPop,Trace]=fmaxga(FUN,LB,UB,eranum,popsize,pcross,pmutation) % Finds a maximum of a function of several variables. % fmaxga solves problems of the form: % max F(X) subject to: LB <= X <= UB % BestPop--------最优的群体即为最优的染色体群 %
Digital_filter
- * CONSTRAINTS * This module does not handle data which is considered out of range by the * application(i.e. fixed constants which represent error condition) * * Maximum weight value must be limited to 128 to prevent an overflow * cond
Electronwatch
- This a vhdl programme for realise an electron watch by max-plus II. The function includes time showing and time setting. It may be extended to other functions like alarming clock and so forth.
rawsource
- RawSource (string filename, int width, int height, string pixel_type, int offset) # for loading raw video data # # filename: the raw file e.g. a YUV-file # width, height: you must specify the image dimensions. width is max 2880 # pixel_type
gl_3ds_loader
- 这是一个opengl下的3ds文件loader。 导入的3ds object 可以用jpeg或者bmp文件作为贴图。 This program loads a 3ds-file with jpeg or bmp texture. Make a model with texture in 3D Studio Max or similar and export it as a 3ds-file. Remember to use the top view in 3D studio as
1i
- 软件测试:一个编译器测试软件,支持下列C语言运算符:+ - * / % ^(乘方) 负 (int) (double) \"字符串\" [](数组) > < == >= <= != && ! ++ -- = += -= *= /= %= ^=,支持下列关键字:void int double string if else for while do goto break continue return,支持下列数据类型:int double string int[] doubl
酒店停车系统
- 1. 用一个包含大小为MAX+1的数组结构体RoomArray来表示客房列表,其数组元素为表示车辆停车信息的结构体GuestNode,用链表队列LinkQueueGuest表示等待队列,其节点元素为表示车辆停车信息的结构体QueueGuest;-1. With a size of MAX contains an array of the structure RoomArray said Rooms to list its array elements to said vehicle parkin
mrdoob-Hi-ReS-Stats-ad6da5d
- Hi-ReS! Stats Performance Monitor This class provides a simple info box that will help you monitor your code performance. So far available for Actionscr ipt and HaXe. * FPS Frames per second, how many frames were rendered in 1 second. Th
3_list
- 三: 针对带表头结点的单链表,试编写下列函数。 (1) 定位函数Locate:在单链表中寻找第i个结点。若找到,则函数返回第i个结点的地址;若找不到,则函数返回NULL。 (2) 求最大值函数max:通过一趟遍历在单链表中确定值最大的结点。 (3) 统计函数number:统计单链表中具有给定值x的所有元素。 (4) 建立函数create:根据一维数组a[n]建立一个单链表,使单链表中各元素的次序与a[n]中各元素的次序相同,要求该程序的时间复杂性为O(n)。 (5) 整理函数
pinv
- //奇异值分解法求广义逆 //本函数返回值小于0表示在奇异值分解过程, //中迭代值超过了60次还未满足精度要求. //返回值大于0表示正常返回。 //a-长度为m*n的数组,返回时其对角线依次给出奇异值,其余元素为0 //m-矩阵的行数 //n-矩阵的列数 //aa-长度为n*m的数组,返回式存放A的广义逆 //eps-精度要求 //u-长度为m*m的数组,返回时存放奇异值分解的左奇异量U //v-长度为n*n的数组,返回时存放奇异值分解的左奇异量
tabtoolbardemo_src
- Because my application required the use of a lot of tools (just like 3DS Max), I decided to implement this control. Here I shall share with you the most important details of creating the tabbed toolbar. The implementation of the control is quite simp
shuzizhong
- 设计一个能进行时、分、秒计时的十二小时制或二十四小时制的数字钟,并具有定时与闹钟功能,能在设定的时间发出闹铃音,能非常方便地对小时、分钟和秒进行手动调节以校准时间,每逢整点,产生报时音报时。 实验平台: 1. 一台PC机; 2. MAX+PLUSII10.1。 Verilog HDL语言实现,还有完整的实验报告-The design of a can be hours, minutes, seconds time of 12 hours or 24 hours system, d
animation
- 从网上找的个小例子。可以显示动画的。它是一张张图片调用的。能用C++builder直接调一个.max的3d动画吗 -From the Internet to find a small example. Can display animation. It is a photo call. Can C++ Builder of a direct transfer. Max for 3d animation you
StereoImage1.0
- 这是我用Delphi和Matlab写的一个程序,可以生成立体图像(3DS Max 脚本)、将平面图像立体化、基本矩阵计算、极线校正。作者保留所有权利。请勿用于商业用途。欢迎大家对它进行完善。-This is what I use Delphi and a program written in Matlab, can generate three-dimensional images (3DS Max scr ipt), will be three-dimensional planar image
waveletcodebyGuleryuz
- Guleryuz写的一个完整的小波变换的源代码。主要包括:wav_basic.c: basic filtering, decimation and upsampling routines. wav_basic.h: interface to wav_basic.c. wav_trf.c: transform routines. wav_trf.h: interface to wav_trf.c. wav_filters.h: where filter banks and the
BtplusV0.1for_Maxz5.0
- BTplus是一套基于马克斯CMS的基础上,免费为马克斯CMS用户提供海量BT资源的下载系统。马克斯CMS是以在线点播影视节目功能为主,而Btplus的出现正好补缺了其影视节目的BT下载功能和内容服务,Btplus与马克斯CMS系统实现完美整合,让您的网站为访客同时提供在线点播和BT下载的完美影视服务。-BTplus is a Max-based CMS on the basis of the free Massive Max CMS users with BT download system
Job
- 给定任务序列J1J2 ...Jn,假定只有一台处理机为这批作业服务。每件任务Ji给定一个时限di和对应利润Pi。只有在规定时限之内完成作业,才会得到利润Pi。通过设计合适的算法选择和安排任务子集Ji,使得J中的每个作业都能在各自的时限内完工,且使获得的利润∑Pi总和最大。 令d=max{di} 1≤i≤n,b=min{n,d} 任何最大利润的可完工子序列中的作业个数必不大于b。 -Given task sequence J1J2 ... Jn, the assumption that
EDAshuzhizhong
- 设计一个能进行时、分、秒计时的十二小时制或二十四小时制的数字钟,并具有定时与闹钟功能,能在设定的时间发出闹铃音,能非常方便地对小时、分钟和秒进行手动调节以校准时间,每逢整点,产生报时音报时。实验平台: 1. 一台PC机; 2. MAX+PLUSII10.1。 Verilog HDL语言实现-The design of a can be hours, minutes, seconds time of 12 hours or 24 hours system, digital clock, and h
travel
- 自己做的vhdl课程设计,交通灯:实现主干道倒计时,分别为30,20,5秒,分情况:当主干道有车时,红黄绿交替,当只一个道路上有车时,那个道的交通灯变绿色,利用max+plus2做成,使用flex8000,epf8282alc84_4只用加一个38译码器模块即可,使用别的板子也可以运行-VHDL to do their own curriculum design, traffic lights: the realization of the trunk road countdown, 30,20
LCS
- Instead of finding the longest common subsequence, let us try to determine the length of the LCS. Then tracking back to find the LCS. Consider a1a2…am and b1b2…bn. Case 1: am=bn. The LCS must contain am, we h